ho 1 triangolo ABC, che può essere scomposto in 2 triangoli: ADB e ADC

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ho 1 triangolo ABC, che può essere scomposto in 2 triangoli: ADB e ADC

by pasquale.clarizio |
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Sinx/Sin12 = Sin(x+30)/Sin30

Sinx/Sin(x+30 = 2Sin12

Sin48

Sinx/Sin(x+30) = 2sin12*Sin48/Sin48

(2Sin12*Sin48 = Sin18 )

Sinx/Sin(x+30) = Sin18/Sin48

X = 18

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