(x, y, z, w) ∈ℝ^4, trovare x^2+y^2+z^2+w^2
(x²,y²,z²,w²)•
[1/3 1/15 1/35 1/63]
|-1/5 1/7 1/27 1/55|
|-1/21 -1/9 1/11 1/39|
[-1/45 -1/33 -1/13 1/15]
=(1 1 1 1)
So (x²,y²,z²,w²)=
(1,1,1,1)•inverse matrix
=(1,1,1,1)*315/47291727872
((344141700,-174561156,418278432),
(408093021,708688035, 4838793960),
(260441784,335624520, -18188089920),
(48583975,85170393, 3631780152))
So x²+y²+z²+w² is sum of all those values from that matrix.
I've got
-48+47186367/92366656
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