avendo un sistema di 2 equazioni, di cui una trigonometrica, coseno, seno
3x+2y=pi/14, so 21x+14y=pi/2.
14y=pi/2-21x
cos5x*cos14y/(sin16x+sin5x*sin14y)
=cos(pi/2-21x)*cos5x/[sin16x+sin(pi/2-21x)*sin5x]
=sin21x*cos5x/(sin16x+cos21x*sin5x]
=sin21x*cos5x/[sin16x+1/2*sin26x-1/2*sin16x]
=sin21x*cos5x/[1/2*(sin26x+sin16x)]
=sin21x*cos5x/(sin21x*cos5x)
=1
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